MRSOT TSXEC OIAPU EMSTS EYCRE IDTTC IM
Since the text consists of 32 characters, the possible rectangles are:
2 x 16
MSTSEOAUMTECEDTI
ROTXCIPESSYRITCM
or 4 x 8
MEME
RCSI
SOTD
OIST
TAET
TPYC
SUCI
XERM
or 8 x 4
MTEAMEET
RTCPSYIC
SSOUTCDI
OXIESRTM
Counting the number of vowels in each row is:
2 x 16
MSTSEOAUMTECEDTI - 7
ROTXCIPESSYRITCM - 5
You would expect to see about 0.4 x 16 or 6.4 vowels per row. This would give a deviation of:
(7.0-6.4) = 0.6
for the first row and a deviation of:
(5.0-6.4) = -1.4
for the second row. The total deviation of all rows would be (ignoring the negative sign) is:
1.4 + 0.6 = 2
and the average deviation would be:
2.0/2.0 = 1.0
This arrangement is unlikely to be the rectangle used to encrypt the message.
or 4 x 8
MEME - 2
RCSI - 1
SOTD - 1
OIST - 2
TAET - 2
TPYC - 1
SUCI - 2
XERM - 1
You would expect to see about 0.4 x 4 or 1.6 vowels per row. This would give deviations of:
(2.0-1.6) = 0.6
(1.0-1.6) = -0.6
(1.0-1.6) = -0.6
(2.0-1.6) = 0.6
(2.0-1.6) = 0.6
(1.0-1.6) = -0.6
(2.0-1.6) = 0.6
(1.0-1.6) = -0.6
The total deviation of all rows would be (ignoring the negative signs) is:
0.6 + 0.6 + 0.6 + 0.6 + 0.6 + 0.6 + 0.6 + 0.6 = 4.8
and the average deviation would be:
4.8/8.0 = 0.6
This arrangement is closer to the expected 0.4 value.
or 8 x 4
MTEAMEET - 4
RTCPSYIC - 2
SSOUTCDI - 3
OXIESRTM - 3
You would expect to see about 0.4 x 8 or 3.2 vowels per row. This would give a deviations of:
(4.0-3.2) = 0.8
(2.0-3.2) = -1.2
(3.0-3.2) = -0.2
(3.0-3.2) = -0.2
The total deviation of all rows would be (ignoring the negative sign) is:
0.8 + 1.2 + 0.2 + 0.2 = 2.4
and the average deviation would be:
2.4/4.0 = 0.6
This arrangement is closer to the expected 0.4 value.
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